Solve for x
x=-\frac{3y}{4}+2
Solve for y
y=\frac{8-4x}{3}
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4x=8-3y
Subtract 3y from both sides.
\frac{4x}{4}=\frac{8-3y}{4}
Divide both sides by 4.
x=\frac{8-3y}{4}
Dividing by 4 undoes the multiplication by 4.
x=-\frac{3y}{4}+2
Divide 8-3y by 4.
3y=8-4x
Subtract 4x from both sides.
\frac{3y}{3}=\frac{8-4x}{3}
Divide both sides by 3.
y=\frac{8-4x}{3}
Dividing by 3 undoes the multiplication by 3.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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