Solve for x
x=-\frac{3y}{4}+12
Solve for y
y=-\frac{4x}{3}+16
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4x=48-3y
Subtract 3y from both sides.
\frac{4x}{4}=\frac{48-3y}{4}
Divide both sides by 4.
x=\frac{48-3y}{4}
Dividing by 4 undoes the multiplication by 4.
x=-\frac{3y}{4}+12
Divide 48-3y by 4.
3y=48-4x
Subtract 4x from both sides.
\frac{3y}{3}=\frac{48-4x}{3}
Divide both sides by 3.
y=\frac{48-4x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{4x}{3}+16
Divide 48-4x by 3.
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