Solve for a
a=\frac{3c}{2}+2x-3b
Solve for b
b=\frac{c}{2}+\frac{2x}{3}-\frac{a}{3}
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2a+6b=4x+3c
Swap sides so that all variable terms are on the left hand side.
2a=4x+3c-6b
Subtract 6b from both sides.
\frac{2a}{2}=\frac{4x+3c-6b}{2}
Divide both sides by 2.
a=\frac{4x+3c-6b}{2}
Dividing by 2 undoes the multiplication by 2.
a=\frac{3c}{2}+2x-3b
Divide 4x+3c-6b by 2.
2a+6b=4x+3c
Swap sides so that all variable terms are on the left hand side.
6b=4x+3c-2a
Subtract 2a from both sides.
\frac{6b}{6}=\frac{4x+3c-2a}{6}
Divide both sides by 6.
b=\frac{4x+3c-2a}{6}
Dividing by 6 undoes the multiplication by 6.
b=\frac{c}{2}+\frac{2x}{3}-\frac{a}{3}
Divide 4x+3c-2a by 6.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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