Solve 4x+2-3ax-a=0

$$4 x + 2 - 3 a x - a = 0$$

Solve for a

$$a=\frac{2\left(2x+1\right)}{3x+1}$$

$$x\neq -\frac{1}{3}$$

Steps for Solving Linear Equation

Subtract 4x from both sides. Anything subtracted from zero gives its negation.

$$2-3ax-a=-4x$$

Subtract 2 from both sides.

$$-3ax-a=-4x-2$$

Combine all terms containing a.

$$\left(-3x-1\right)a=-4x-2$$

Divide both sides by -3x-1.

$$\frac{\left(-3x-1\right)a}{-3x-1}=\frac{-4x-2}{-3x-1}$$

Dividing by -3x-1 undoes the multiplication by -3x-1.

$$a=\frac{-4x-2}{-3x-1}$$

Divide -4x-2 by -3x-1.

$$a=\frac{2\left(2x+1\right)}{3x+1}$$

Solve for x

$$x=-\frac{2-a}{4-3a}$$

$$a\neq \frac{4}{3}$$

Steps for Solving Linear Equation

Subtract 2 from both sides. Anything subtracted from zero gives its negation.

$$4x-3ax-a=-2$$

Add a to both sides.

$$4x-3ax=-2+a$$

Combine all terms containing x.

$$\left(4-3a\right)x=-2+a$$

The equation is in standard form.

$$\left(4-3a\right)x=a-2$$

Divide both sides by 4-3a.

$$\frac{\left(4-3a\right)x}{4-3a}=\frac{a-2}{4-3a}$$

Dividing by 4-3a undoes the multiplication by 4-3a.

$$x=\frac{a-2}{4-3a}$$