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Solve for w_2, w
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4w_{2}-9\left(6-5\times 3\right)=44
Consider the first equation. Insert the known values of variables into the equation.
4w_{2}-9\left(6-15\right)=44
Multiply -5 and 3 to get -15.
4w_{2}-9\left(-9\right)=44
Subtract 15 from 6 to get -9.
4w_{2}+81=44
Multiply -9 and -9 to get 81.
4w_{2}=44-81
Subtract 81 from both sides.
4w_{2}=-37
Subtract 81 from 44 to get -37.
w_{2}=-\frac{37}{4}
Divide both sides by 4.
w_{2}=-\frac{37}{4} w=3
The system is now solved.