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w^{2}\left(4w-3\right)+4w-3
Do the grouping 4w^{3}-3w^{2}+4w-3=\left(4w^{3}-3w^{2}\right)+\left(4w-3\right), and factor out w^{2} in 4w^{3}-3w^{2}.
\left(4w-3\right)\left(w^{2}+1\right)
Factor out common term 4w-3 by using distributive property. Polynomial w^{2}+1 is not factored since it does not have any rational roots.