Solve 4u-8x-1=0

$$4 u - 8 x - 1 = 0$$

Solve for u

$$u=2x+\frac{1}{4}$$

Steps for Solving Linear Equation

Add 8x to both sides. Anything plus zero gives itself.

$$4u-1=8x$$

Add 1 to both sides.

$$4u=8x+1$$

Divide both sides by 4.

$$\frac{4u}{4}=\frac{8x+1}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$u=\frac{8x+1}{4}$$

Divide 8x+1 by 4.

$$u=2x+\frac{1}{4}$$

Solve for x

$$x=\frac{u}{2}-\frac{1}{8}$$

Steps for Solving Linear Equation

Subtract 4u from both sides. Anything subtracted from zero gives its negation.

$$-8x-1=-4u$$

Add 1 to both sides.

$$-8x=-4u+1$$

The equation is in standard form.

$$-8x=1-4u$$

Divide both sides by -8.

$$\frac{-8x}{-8}=\frac{1-4u}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$x=\frac{1-4u}{-8}$$

Divide -4u+1 by -8.

$$x=\frac{u}{2}-\frac{1}{8}$$