Solve 4u^4-64u^2

$$4 u ^ { 4 } - 64 u ^ { 2 }$$

Factor

$$4\left(u-4\right)\left(u+4\right)u^{2}$$

Solution Steps

Factor out 4.

$$4\left(u^{4}-16u^{2}\right)$$

Consider u^{4}-16u^{2}. Factor out u^{2}.

$$u^{2}\left(u^{2}-16\right)$$

Consider u^{2}-16. Rewrite u^{2}-16 as u^{2}-4^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(u-4\right)\left(u+4\right)$$

Rewrite the complete factored expression.

$$4u^{2}\left(u-4\right)\left(u+4\right)$$

Evaluate

$$4u^{2}\left(u^{2}-16\right)$$