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u^{2}\left(4u+3\right)+7\left(4u+3\right)
Do the grouping 4u^{3}+3u^{2}+28u+21=\left(4u^{3}+3u^{2}\right)+\left(28u+21\right), and factor out u^{2} in the first and 7 in the second group.
\left(4u+3\right)\left(u^{2}+7\right)
Factor out common term 4u+3 by using distributive property. Polynomial u^{2}+7 is not factored since it does not have any rational roots.