Solve 4t^3*3t^2+6t^4

$$4 t ^ { 3 } \times 3 t ^ { 2 } + 6 t ^ { 4 }$$

Evaluate

$$6\left(2t+1\right)t^{4}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 2 to get 5.

$$4t^{5}\times 3+6t^{4}$$

Multiply 4 and 3 to get 12.

$$12t^{5}+6t^{4}$$

Factor

$$6\left(2t+1\right)t^{4}$$

Solution Steps

Factor out 6.

$$6\left(2t^{3}t^{2}+t^{4}\right)$$

Consider 2t^{5}+t^{4}. Factor out t^{4}.

$$t^{4}\left(2t+1\right)$$

Rewrite the complete factored expression.

$$6t^{4}\left(2t+1\right)$$