Solve 4r^2+4n+36=0

$$4 r ^ { 2 } + 4 n + 36 = 0$$

Solve for n (complex solution)

$$n=-r^{2}-9$$

Steps for Solving Linear Equation

Subtract 4r^{2} from both sides. Anything subtracted from zero gives its negation.

$$4n+36=-4r^{2}$$

Subtract 36 from both sides.

$$4n=-4r^{2}-36$$

Divide both sides by 4.

$$\frac{4n}{4}=\frac{-4r^{2}-36}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$n=\frac{-4r^{2}-36}{4}$$

Divide -4r^{2}-36 by 4.

$$n=\left(3i-r\right)\left(r+3i\right)$$

Solve for n

$$n=-\left(r^{2}+9\right)$$

Steps for Solving Linear Equation

Subtract 4r^{2} from both sides. Anything subtracted from zero gives its negation.

$$4n+36=-4r^{2}$$

Subtract 36 from both sides.

$$4n=-4r^{2}-36$$

Divide both sides by 4.

$$\frac{4n}{4}=\frac{-4r^{2}-36}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$n=\frac{-4r^{2}-36}{4}$$

Divide -4r^{2}-36 by 4.

$$n=-r^{2}-9$$

Solve for r (complex solution)

$$r=-i\sqrt{n+9}$$

$$r=i\sqrt{n+9}$$

Solve for r

$$r=\sqrt{-n-9}$$

$$r=-\sqrt{-n-9}\text{, }n\leq -9$$