Solve for D
D=\frac{1}{n^{3}}
n\neq 0
Solve for n (complex solution)
n=e^{\frac{2\pi i}{3}}D^{-\frac{1}{3}}
n=D^{-\frac{1}{3}}
n=e^{\frac{4\pi i}{3}}D^{-\frac{1}{3}}\text{, }D\neq 0
Solve for n
n=\frac{1}{\sqrt[3]{D}}
D\neq 0
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4nDn^{2}=4
Multiply both sides of the equation by n^{2}.
4n^{3}D=4
To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.
\frac{4n^{3}D}{4n^{3}}=\frac{4}{4n^{3}}
Divide both sides by 4n^{3}.
D=\frac{4}{4n^{3}}
Dividing by 4n^{3} undoes the multiplication by 4n^{3}.
D=\frac{1}{n^{3}}
Divide 4 by 4n^{3}.
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