Solve 4n^2+44n+96

$$4 n ^ { 2 } + 44 n + 96$$

Factor

$$4\left(n+3\right)\left(n+8\right)$$

Solution Steps

Factor out 4.

$$4\left(n^{2}+11n+24\right)$$

Consider n^{2}+11n+24. Factor the expression by grouping. First, the expression needs to be rewritten as n^{2}+an+bn+24. To find a and b, set up a system to be solved.

$$a+b=11 ab=1\times 24=24$$

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 24.

$$1,24 2,12 3,8 4,6$$

Calculate the sum for each pair.

$$1+24=25 2+12=14 3+8=11 4+6=10$$

The solution is the pair that gives sum 11.

$$a=3 b=8$$

Rewrite n^{2}+11n+24 as \left(n^{2}+3n\right)+\left(8n+24\right).

$$\left(n^{2}+3n\right)+\left(8n+24\right)$$

Factor out n in the first and 8 in the second group.

$$n\left(n+3\right)+8\left(n+3\right)$$

Factor out common term n+3 by using distributive property.

$$\left(n+3\right)\left(n+8\right)$$

Rewrite the complete factored expression.

$$4\left(n+3\right)\left(n+8\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$4n^{2}+44n+96=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$n=\frac{-44±\sqrt{44^{2}-4\times 4\times 96}}{2\times 4}$$

Square 44.

$$n=\frac{-44±\sqrt{1936-4\times 4\times 96}}{2\times 4}$$

Multiply -4 times 4.

$$n=\frac{-44±\sqrt{1936-16\times 96}}{2\times 4}$$

Multiply -16 times 96.

$$n=\frac{-44±\sqrt{1936-1536}}{2\times 4}$$

Add 1936 to -1536.

$$n=\frac{-44±\sqrt{400}}{2\times 4}$$

Take the square root of 400.

$$n=\frac{-44±20}{2\times 4}$$

Multiply 2 times 4.

$$n=\frac{-44±20}{8}$$

Now solve the equation n=\frac{-44±20}{8} when ± is plus. Add -44 to 20.

$$n=-\frac{24}{8}$$

Divide -24 by 8.

$$n=-3$$

Now solve the equation n=\frac{-44±20}{8} when ± is minus. Subtract 20 from -44.

$$n=-\frac{64}{8}$$

Divide -64 by 8.

$$n=-8$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute -3 for x_{1} and -8 for x_{2}.

$$4n^{2}+44n+96=4\left(n-\left(-3\right)\right)\left(n-\left(-8\right)\right)$$

Simplify all the expressions of the form p-\left(-q\right) to p+q.

$$4n^{2}+44n+96=4\left(n+3\right)\left(n+8\right)$$

Steps Using Direct Factoring Method

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 4

$$x ^ 2 +11x +24 = 0$$

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

$$r + s = -11 rs = 24$$

Two numbers r and s sum up to -11 exactly when the average of the two numbers is \frac{1}{2}*-11 = -\frac{11}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>

$$r = -\frac{11}{2} - u s = -\frac{11}{2} + u$$

To solve for unknown quantity u, substitute these in the product equation rs = 24

$$(-\frac{11}{2} - u) (-\frac{11}{2} + u) = 24$$

Simplify by expanding (a -b) (a + b) = a^2 – b^2

$$\frac{121}{4} - u^2 = 24$$

Simplify the expression by subtracting \frac{121}{4} on both sides

$$-u^2 = 24-\frac{121}{4} = -\frac{25}{4}$$

Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u

$$u^2 = \frac{25}{4} u = \pm\sqrt{\frac{25}{4}} = \pm \frac{5}{2}$$

The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.

$$r =-\frac{11}{2} - \frac{5}{2} = -8 s = -\frac{11}{2} + \frac{5}{2} = -3$$

Evaluate

$$4\left(n+3\right)\left(n+8\right)$$