Solve 4n+40leq5.5n

$$4 n + 40 \leq 5.5 n$$

Solve for n

$$n\geq \frac{80}{3}$$

Solution Steps

Subtract 5.5n from both sides.

$$4n+40-5.5n\leq 0$$

Combine 4n and -5.5n to get -1.5n.

$$-1.5n+40\leq 0$$

Subtract 40 from both sides. Anything subtracted from zero gives its negation.

$$-1.5n\leq -40$$

Divide both sides by -1.5. Since -1.5 is negative, the inequality direction is changed.

$$n\geq \frac{-40}{-1.5}$$

Expand \frac{-40}{-1.5} by multiplying both numerator and the denominator by 10.

$$n\geq \frac{-400}{-15}$$

Reduce the fraction \frac{-400}{-15} to lowest terms by extracting and canceling out -5.

$$n\geq \frac{80}{3}$$