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4m^{2}=-76
Subtract 76 from both sides. Anything subtracted from zero gives its negation.
m^{2}=\frac{-76}{4}
Divide both sides by 4.
m^{2}=-19
Divide -76 by 4 to get -19.
m=\sqrt{19}i m=-\sqrt{19}i
The equation is now solved.
4m^{2}+76=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
m=\frac{0±\sqrt{0^{2}-4\times 4\times 76}}{2\times 4}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 4 for a, 0 for b, and 76 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
m=\frac{0±\sqrt{-4\times 4\times 76}}{2\times 4}
Square 0.
m=\frac{0±\sqrt{-16\times 76}}{2\times 4}
Multiply -4 times 4.
m=\frac{0±\sqrt{-1216}}{2\times 4}
Multiply -16 times 76.
m=\frac{0±8\sqrt{19}i}{2\times 4}
Take the square root of -1216.
m=\frac{0±8\sqrt{19}i}{8}
Multiply 2 times 4.
m=\sqrt{19}i
Now solve the equation m=\frac{0±8\sqrt{19}i}{8} when ± is plus.
m=-\sqrt{19}i
Now solve the equation m=\frac{0±8\sqrt{19}i}{8} when ± is minus.
m=\sqrt{19}i m=-\sqrt{19}i
The equation is now solved.