Solve 4m^2+12n=8

$$4 m ^ { 2 } + 12 n = 8$$

Solve for n

$$n=\frac{2-m^{2}}{3}$$

Steps for Solving Linear Equation

Subtract 4m^{2} from both sides.

$$12n=8-4m^{2}$$

Divide both sides by 12.

$$\frac{12n}{12}=\frac{8-4m^{2}}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$n=\frac{8-4m^{2}}{12}$$

Divide 8-4m^{2} by 12.

$$n=\frac{2-m^{2}}{3}$$

Solve for m (complex solution)

$$m=-\sqrt{2-3n}$$

$$m=\sqrt{2-3n}$$

Solve for m

$$m=\sqrt{2-3n}$$

$$m=-\sqrt{2-3n}\text{, }n\leq \frac{2}{3}$$