Solve 4m^{-3}n^-2*-4m^-1n^-3*-6n^2=

$$4 m ^ { - 3 } n ^ { - 2 } \cdot - 4 m ^ { - 1 } n ^ { - 3 } \cdot - 6 n ^ { 2 } =$$

Evaluate

$$\frac{96}{n^{3}m^{4}}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add -3 and -1 to get -4.

$$4m^{-4}n^{-2}\left(-4\right)n^{-3}\left(-6\right)n^{2}$$

To multiply powers of the same base, add their exponents. Add -2 and -3 to get -5.

$$4m^{-4}n^{-5}\left(-4\right)\left(-6\right)n^{2}$$

To multiply powers of the same base, add their exponents. Add -5 and 2 to get -3.

$$4m^{-4}n^{-3}\left(-4\right)\left(-6\right)$$

Multiply 4 and -4 to get -16.

$$-16m^{-4}n^{-3}\left(-6\right)$$

Multiply -16 and -6 to get 96.

$$96m^{-4}n^{-3}$$

Differentiate w.r.t. m

$$-\frac{384}{n^{3}m^{5}}$$