Solve 4isqrt{8}(-2isqrt{3})

$$4 i \sqrt { 8 } ( - 2 i \sqrt { 3 } )$$

Evaluate

$$16\sqrt{6}\approx 39.191835885$$

Solution Steps

Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.

$$4i\times 2\sqrt{2}\times \left(-2i\right)\sqrt{3}$$

Multiply 4i and 2 to get 8i.

$$8i\sqrt{2}\times \left(-2i\right)\sqrt{3}$$

Multiply 8i and -2i to get 16.

$$16\sqrt{2}\sqrt{3}$$

To multiply \sqrt{2} and \sqrt{3}, multiply the numbers under the square root.

$$16\sqrt{6}$$

Real Part

$$16 \sqrt{6} = 39.191835885$$