Solve 4i^3+6i^15=

$$4 i ^ { 3 } + 6 i ^ { 15 } =$$

Evaluate

$$-10i$$

Solution Steps

Calculate i to the power of 3 and get -i.

$$4\left(-i\right)+6i^{15}$$

Multiply 4 and -i to get -4i.

$$-4i+6i^{15}$$

Calculate i to the power of 15 and get -i.

$$-4i+6\left(-i\right)$$

Multiply 6 and -i to get -6i.

$$-4i-6i$$

Subtract 6i from -4i to get -10i.

$$-10i$$

Real Part

$$0$$

Solution Steps

Calculate i to the power of 3 and get -i.

$$Re(4\left(-i\right)+6i^{15})$$

Multiply 4 and -i to get -4i.

$$Re(-4i+6i^{15})$$

Calculate i to the power of 15 and get -i.

$$Re(-4i+6\left(-i\right))$$

Multiply 6 and -i to get -6i.

$$Re(-4i-6i)$$

Subtract 6i from -4i to get -10i.

$$Re(-10i)$$

The real part of -10i is 0.

$$0$$