Solve 4h^2-90p+504=0

$$4 h ^ { 2 } - 90 p + 504 = 0$$

Solve for p

$$p=\frac{2\left(h^{2}+126\right)}{45}$$

Steps for Solving Linear Equation

Subtract 4h^{2} from both sides. Anything subtracted from zero gives its negation.

$$-90p+504=-4h^{2}$$

Subtract 504 from both sides.

$$-90p=-4h^{2}-504$$

Divide both sides by -90.

$$\frac{-90p}{-90}=\frac{-4h^{2}-504}{-90}$$

Dividing by -90 undoes the multiplication by -90.

$$p=\frac{-4h^{2}-504}{-90}$$

Divide -4h^{2}-504 by -90.

$$p=\frac{2h^{2}}{45}+\frac{28}{5}$$

Solve for h

$$h=\frac{3\sqrt{10p-56}}{2}$$

$$h=-\frac{3\sqrt{10p-56}}{2}\text{, }p\geq \frac{28}{5}$$