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f^{2}\left(4f+1\right)+3\left(4f+1\right)
Do the grouping 4f^{3}+f^{2}+12f+3=\left(4f^{3}+f^{2}\right)+\left(12f+3\right), and factor out f^{2} in the first and 3 in the second group.
\left(4f+1\right)\left(f^{2}+3\right)
Factor out common term 4f+1 by using distributive property. Polynomial f^{2}+3 is not factored since it does not have any rational roots.