Solve 4c(4c-1)-3(4c-1)^2

$$4 c ( 4 c - 1 ) - 3 ( 4 c - 1 ) ^ { 2 }$$

Evaluate

$$\left(3-8c\right)\left(4c-1\right)$$

Solution Steps

Use the distributive property to multiply 4c by 4c-1.

$$16c^{2}-4c-3\left(4c-1\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4c-1\right)^{2}.

$$16c^{2}-4c-3\left(16c^{2}-8c+1\right)$$

Use the distributive property to multiply -3 by 16c^{2}-8c+1.

$$16c^{2}-4c-48c^{2}+24c-3$$

Combine 16c^{2} and -48c^{2} to get -32c^{2}.

$$-32c^{2}-4c+24c-3$$

Combine -4c and 24c to get 20c.

$$-32c^{2}+20c-3$$

Expand

$$-32c^{2}+20c-3$$

Solution Steps

Use the distributive property to multiply 4c by 4c-1.

$$16c^{2}-4c-3\left(4c-1\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4c-1\right)^{2}.

$$16c^{2}-4c-3\left(16c^{2}-8c+1\right)$$

Use the distributive property to multiply -3 by 16c^{2}-8c+1.

$$16c^{2}-4c-48c^{2}+24c-3$$

Combine 16c^{2} and -48c^{2} to get -32c^{2}.

$$-32c^{2}-4c+24c-3$$

Combine -4c and 24c to get 20c.

$$-32c^{2}+20c-3$$