Solve 4b-4-12b-5

$$4 b - 4 - 12 b - 5$$

Evaluate

$$-8b-9$$

Solution Steps

Combine 4b and -12b to get -8b.

$$-8b-4-5$$

Subtract 5 from -4 to get -9.

$$-8b-9$$

Differentiate w.r.t. b

$$-8$$

Steps Using Derivative Rule for Sum

Combine 4b and -12b to get -8b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-8b-4-5)$$

Subtract 5 from -4 to get -9.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-8b-9)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-8b^{1-1}$$

Subtract 1 from 1.

$$-8b^{0}$$

For any term t except 0, t^{0}=1.

$$-8$$