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b^{2}\left(4b+1\right)+2\left(4b+1\right)
Do the grouping 4b^{3}+b^{2}+8b+2=\left(4b^{3}+b^{2}\right)+\left(8b+2\right), and factor out b^{2} in the first and 2 in the second group.
\left(4b+1\right)\left(b^{2}+2\right)
Factor out common term 4b+1 by using distributive property. Polynomial b^{2}+2 is not factored since it does not have any rational roots.