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\frac{64b^{16}-d^{4}}{16}
Factor out \frac{1}{16}.
\left(8b^{8}-d^{2}\right)\left(8b^{8}+d^{2}\right)
Consider 64b^{16}-d^{4}. Rewrite 64b^{16}-d^{4} as \left(8b^{8}\right)^{2}-\left(d^{2}\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).
\frac{\left(8b^{8}-d^{2}\right)\left(8b^{8}+d^{2}\right)}{16}
Rewrite the complete factored expression.