Solve 4b^-3(-1)^3-4(-1)^2(-1)+(-1)^2

$$4 b ^ { - 3 } ( - 1 ) ^ { 3 } - 4 ( - 1 ) ^ { 2 } ( - 1 ) + ( - 1 ) ^ { 2 }$$

Evaluate

$$5-\frac{4}{b^{3}}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$4b^{-3}\left(-1\right)^{3}-4\left(-1\right)^{3}+\left(-1\right)^{2}$$

Calculate -1 to the power of 3 and get -1.

$$4b^{-3}\left(-1\right)-4\left(-1\right)^{3}+\left(-1\right)^{2}$$

Multiply 4 and -1 to get -4.

$$-4b^{-3}-4\left(-1\right)^{3}+\left(-1\right)^{2}$$

Calculate -1 to the power of 3 and get -1.

$$-4b^{-3}-4\left(-1\right)+\left(-1\right)^{2}$$

Multiply 4 and -1 to get -4.

$$-4b^{-3}-\left(-4\right)+\left(-1\right)^{2}$$

The opposite of -4 is 4.

$$-4b^{-3}+4+\left(-1\right)^{2}$$

Calculate -1 to the power of 2 and get 1.

$$-4b^{-3}+4+1$$

Add 4 and 1 to get 5.

$$-4b^{-3}+5$$

Factor

$$\frac{5b^{3}-4}{b^{3}}$$