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Solve for b
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4b+3c=30xy
Multiply 6 and 5 to get 30.
4b=30xy-3c
Subtract 3c from both sides.
\frac{4b}{4}=\frac{30xy-3c}{4}
Divide both sides by 4.
b=\frac{30xy-3c}{4}
Dividing by 4 undoes the multiplication by 4.
b=\frac{15xy}{2}-\frac{3c}{4}
Divide 30xy-3c by 4.
4b+3c=30xy
Multiply 6 and 5 to get 30.
3c=30xy-4b
Subtract 4b from both sides.
\frac{3c}{3}=\frac{30xy-4b}{3}
Divide both sides by 3.
c=\frac{30xy-4b}{3}
Dividing by 3 undoes the multiplication by 3.
c=10xy-\frac{4b}{3}
Divide 30xy-4b by 3.