Solve 4a-3ab+4b=0

$$4 a - 3 a b + 4 b = 0$$

Solve for a

$$a=-\frac{4b}{4-3b}$$

$$b\neq \frac{4}{3}$$

Steps for Solving Linear Equation

Subtract 4b from both sides. Anything subtracted from zero gives its negation.

$$4a-3ab=-4b$$

Combine all terms containing a.

$$\left(4-3b\right)a=-4b$$

Divide both sides by 4-3b.

$$\frac{\left(4-3b\right)a}{4-3b}=-\frac{4b}{4-3b}$$

Dividing by 4-3b undoes the multiplication by 4-3b.

$$a=-\frac{4b}{4-3b}$$

Solve for b

$$b=-\frac{4a}{4-3a}$$

$$a\neq \frac{4}{3}$$

Steps for Solving Linear Equation

Subtract 4a from both sides. Anything subtracted from zero gives its negation.

$$-3ab+4b=-4a$$

Combine all terms containing b.

$$\left(-3a+4\right)b=-4a$$

The equation is in standard form.

$$\left(4-3a\right)b=-4a$$

Divide both sides by -3a+4.

$$\frac{\left(4-3a\right)b}{4-3a}=-\frac{4a}{4-3a}$$

Dividing by -3a+4 undoes the multiplication by -3a+4.

$$b=-\frac{4a}{4-3a}$$