Factor
\left(2ab-7n^{3}\right)\left(7n^{3}+2ab\right)
Evaluate
4\left(ab\right)^{2}-49n^{6}
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\left(2ab-7n^{3}\right)\left(2ab+7n^{3}\right)
Rewrite 4a^{2}b^{2}-49n^{6} as \left(2ab\right)^{2}-\left(7n^{3}\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).
\left(-7n^{3}+2ab\right)\left(7n^{3}+2ab\right)
Reorder the terms.
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