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4a^{2}-\left(b^{2}-6bc+9c^{2}\right)
Rewrite as difference of two terms.
\left(2a\right)^{2}-\left(b-3c\right)^{2}
Rewrite the terms as squares.
\left(2a-b+3c\right)\left(2a+b-3c\right)
The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).