Solve 4a^2-4a+3=(4a^2+10a+9)

$$4 a ^ { 2 } - 4 a + 3 = ( 4 a ^ { 2 } + 10 a + 9 )$$

Solve for a

$$a=-\frac{3}{7}\approx -0.428571429$$

Steps for Solving Linear Equation

Subtract 4a^{2} from both sides.

$$4a^{2}-4a+3-4a^{2}=10a+9$$

Combine 4a^{2} and -4a^{2} to get 0.

$$-4a+3=10a+9$$

Subtract 10a from both sides.

$$-4a+3-10a=9$$

Combine -4a and -10a to get -14a.

$$-14a+3=9$$

Subtract 3 from both sides.

$$-14a=9-3$$

Subtract 3 from 9 to get 6.

$$-14a=6$$

Divide both sides by -14.

$$a=\frac{6}{-14}$$

Reduce the fraction \frac{6}{-14} to lowest terms by extracting and canceling out 2.

$$a=-\frac{3}{7}$$