Solve 4a^2+2b+2c=0

$$4 a ^ { 2 } + 2 b + 2 c = 0$$

Solve for b

$$b=-\left(2a^{2}+c\right)$$

Steps for Solving Linear Equation

Subtract 4a^{2} from both sides. Anything subtracted from zero gives its negation.

$$2b+2c=-4a^{2}$$

Subtract 2c from both sides.

$$2b=-4a^{2}-2c$$

Divide both sides by 2.

$$\frac{2b}{2}=\frac{-4a^{2}-2c}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$b=\frac{-4a^{2}-2c}{2}$$

Divide -4a^{2}-2c by 2.

$$b=-2a^{2}-c$$

Solve for a

$$a=\frac{\sqrt{-2b-2c}}{2}$$

$$a=-\frac{\sqrt{-2b-2c}}{2}\text{, }b\leq -c$$