Solve 4a+2b=3

$$4 a + 2 b = 3$$

Solve for a

$$a=-\frac{b}{2}+\frac{3}{4}$$

Steps for Solving Linear Equation

Subtract 2b from both sides.

$$4a=3-2b$$

Divide both sides by 4.

$$\frac{4a}{4}=\frac{3-2b}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$a=\frac{3-2b}{4}$$

Divide 3-2b by 4.

$$a=-\frac{b}{2}+\frac{3}{4}$$

Solve for b

$$b=\frac{3}{2}-2a$$

Steps for Solving Linear Equation

Subtract 4a from both sides.

$$2b=3-4a$$

Divide both sides by 2.

$$\frac{2b}{2}=\frac{3-4a}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$b=\frac{3-4a}{2}$$

Divide 3-4a by 2.

$$b=\frac{3}{2}-2a$$