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4-x=3-2\sqrt{2}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
-x=3-2\sqrt{2}-4
Subtract 4 from both sides.
-x=-1-2\sqrt{2}
Subtract 4 from 3 to get -1.
-x=-2\sqrt{2}-1
The equation is in standard form.
\frac{-x}{-1}=\frac{-2\sqrt{2}-1}{-1}
Divide both sides by -1.
x=\frac{-2\sqrt{2}-1}{-1}
Dividing by -1 undoes the multiplication by -1.
x=2\sqrt{2}+1
Divide -1-2\sqrt{2} by -1.