Solve 4-4k+k^2+4

$$4 - 4 k + k ^ { 2 } + 4$$

Differentiate w.r.t. k

$$2\left(k-2\right)$$

Steps Using Derivative Rule for Sum

Add 4 and 4 to get 8.

$$\frac{\mathrm{d}}{\mathrm{d}k}(8-4k+k^{2})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-4k^{1-1}+2k^{2-1}$$

Subtract 1 from 1.

$$-4k^{0}+2k^{2-1}$$

Subtract 1 from 2.

$$-4k^{0}+2k^{1}$$

For any term t, t^{1}=t.

$$-4k^{0}+2k$$

For any term t except 0, t^{0}=1.

$$-4+2k$$

Evaluate

$$k^{2}-4k+8$$

Solution Steps

Add 4 and 4 to get 8.

$$8-4k+k^{2}$$