Solve 4-4(2-1)div2-3(-6)div(-9)+6

$$4 - 4 ( 2 - 1 ) \div 2 - 3 ( - 6 ) \div ( - 9 ) + 6$$

Evaluate

$$6$$

Solution Steps

Subtract 1 from 2 to get 1.

$$4-\frac{4\times 1}{2}-\frac{3\left(-6\right)}{-9}+6$$

Multiply 4 and 1 to get 4.

$$4-\frac{4}{2}-\frac{3\left(-6\right)}{-9}+6$$

Divide 4 by 2 to get 2.

$$4-2-\frac{3\left(-6\right)}{-9}+6$$

Subtract 2 from 4 to get 2.

$$2-\frac{3\left(-6\right)}{-9}+6$$

Multiply 3 and -6 to get -18.

$$2-\frac{-18}{-9}+6$$

Divide -18 by -9 to get 2.

$$2-2+6$$

Subtract 2 from 2 to get 0.

$$6$$

Factor

$$2\times 3$$