Solve 4-3xleq-3/4

$$4 - 3 x \leq - \frac { 3 } { 4 }$$

Solve for x

$$x\geq \frac{19}{12}$$

Solution Steps

Subtract 4 from both sides.

$$-3x\leq -\frac{3}{4}-4$$

Convert 4 to fraction \frac{16}{4}.

$$-3x\leq -\frac{3}{4}-\frac{16}{4}$$

Since -\frac{3}{4} and \frac{16}{4} have the same denominator, subtract them by subtracting their numerators.

$$-3x\leq \frac{-3-16}{4}$$

Subtract 16 from -3 to get -19.

$$-3x\leq -\frac{19}{4}$$

Divide both sides by -3. Since -3 is negative, the inequality direction is changed.

$$x\geq \frac{-\frac{19}{4}}{-3}$$

Express \frac{-\frac{19}{4}}{-3} as a single fraction.

$$x\geq \frac{-19}{4\left(-3\right)}$$

Multiply 4 and -3 to get -12.

$$x\geq \frac{-19}{-12}$$

Fraction \frac{-19}{-12} can be simplified to \frac{19}{12} by removing the negative sign from both the numerator and the denominator.

$$x\geq \frac{19}{12}$$