Solve 4-3(4/3-3/2)

$$4 - 3 ( \frac { 4 } { 3 } - \frac { 3 } { 2 } )$$

Evaluate

$$\frac{9}{2}=4.5$$

Solution Steps

Least common multiple of 3 and 2 is 6. Convert \frac{4}{3} and \frac{3}{2} to fractions with denominator 6.

$$4-3\left(\frac{8}{6}-\frac{9}{6}\right)$$

Since \frac{8}{6} and \frac{9}{6} have the same denominator, subtract them by subtracting their numerators.

$$4-3\times \frac{8-9}{6}$$

Subtract 9 from 8 to get -1.

$$4-3\left(-\frac{1}{6}\right)$$

Express 3\left(-\frac{1}{6}\right) as a single fraction.

$$4-\frac{3\left(-1\right)}{6}$$

Multiply 3 and -1 to get -3.

$$4-\frac{-3}{6}$$

Reduce the fraction \frac{-3}{6} to lowest terms by extracting and canceling out 3.

$$4-\left(-\frac{1}{2}\right)$$

The opposite of -\frac{1}{2} is \frac{1}{2}.

$$4+\frac{1}{2}$$

Convert 4 to fraction \frac{8}{2}.

$$\frac{8}{2}+\frac{1}{2}$$

Since \frac{8}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{8+1}{2}$$

Add 8 and 1 to get 9.

$$\frac{9}{2}$$

Factor

$$\frac{3 ^ {2}}{2} = 4\frac{1}{2} = 4.5$$