Solve 4-3[4-2(6-3)]+2

$$4 - 3 [ 4 - 2 ( 6 - 3 ) ] + 2$$

Evaluate

$$12$$

Solution Steps

Subtract 3 from 6 to get 3.

$$4-3\left(4-2\times 3\right)+2$$

Multiply 2 and 3 to get 6.

$$4-3\left(4-6\right)+2$$

Subtract 6 from 4 to get -2.

$$4-3\left(-2\right)+2$$

Multiply 3 and -2 to get -6.

$$4-\left(-6\right)+2$$

The opposite of -6 is 6.

$$4+6+2$$

Add 4 and 6 to get 10.

$$10+2$$

Add 10 and 2 to get 12.

$$12$$

Factor

$$2^{2}\times 3$$