Solve 4-2|3|+{4-3(2-4)}

$$4 - 2 | 3 | + \{ 4 - 3 ( 2 - 4 ) \}$$

Evaluate

$$8$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 3 is 3.

$$4-2\times 3+4-3\left(2-4\right)$$

Multiply 2 and 3 to get 6.

$$4-6+4-3\left(2-4\right)$$

Subtract 6 from 4 to get -2.

$$-2+4-3\left(2-4\right)$$

Subtract 4 from 2 to get -2.

$$-2+4-3\left(-2\right)$$

Multiply 3 and -2 to get -6.

$$-2+4-\left(-6\right)$$

The opposite of -6 is 6.

$$-2+4+6$$

Add 4 and 6 to get 10.

$$-2+10$$

Add -2 and 10 to get 8.

$$8$$

Factor

$$2^{3}$$