Solve 4-2^3+2-4(2-3)+2*sqrt{25}

$$4 - 2 ^ { 3 } + 2 - 4 ( 2 - 3 ) + 2 \times \sqrt { 25 }$$

Evaluate

$$12$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$4-8+2-4\left(2-3\right)+2\sqrt{25}$$

Subtract 8 from 4 to get -4.

$$-4+2-4\left(2-3\right)+2\sqrt{25}$$

Add -4 and 2 to get -2.

$$-2-4\left(2-3\right)+2\sqrt{25}$$

Subtract 3 from 2 to get -1.

$$-2-4\left(-1\right)+2\sqrt{25}$$

Multiply 4 and -1 to get -4.

$$-2-\left(-4\right)+2\sqrt{25}$$

The opposite of -4 is 4.

$$-2+4+2\sqrt{25}$$

Add -2 and 4 to get 2.

$$2+2\sqrt{25}$$

Calculate the square root of 25 and get 5.

$$2+2\times 5$$

Multiply 2 and 5 to get 10.

$$2+10$$

Add 2 and 10 to get 12.

$$12$$

Factor

$$2^{2}\times 3$$