Solve 4-(a-3)^2

$$4 - ( a - 3 ) ^ { 2 }$$

Evaluate

$$\left(1-a\right)\left(a-5\right)$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(a-3\right)^{2}.

$$4-\left(a^{2}-6a+9\right)$$

To find the opposite of a^{2}-6a+9, find the opposite of each term.

$$4-a^{2}+6a-9$$

Subtract 9 from 4 to get -5.

$$-5-a^{2}+6a$$

Expand

$$-a^{2}+6a-5$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(a-3\right)^{2}.

$$4-\left(a^{2}-6a+9\right)$$

To find the opposite of a^{2}-6a+9, find the opposite of each term.

$$4-a^{2}+6a-9$$

Subtract 9 from 4 to get -5.

$$-5-a^{2}+6a$$