Solve for x
x=10
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4-3x-\left(-5\right)=6-\left(2x+7\right)
To find the opposite of 3x-5, find the opposite of each term.
4-3x+5=6-\left(2x+7\right)
The opposite of -5 is 5.
9-3x=6-\left(2x+7\right)
Add 4 and 5 to get 9.
9-3x=6-2x-7
To find the opposite of 2x+7, find the opposite of each term.
9-3x=-1-2x
Subtract 7 from 6 to get -1.
9-3x+2x=-1
Add 2x to both sides.
9-x=-1
Combine -3x and 2x to get -x.
-x=-1-9
Subtract 9 from both sides.
-x=-10
Subtract 9 from -1 to get -10.
x=10
Multiply both sides by -1.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}