Solve 4(y-1)+3(y+2)=5(y-4)

$$4 ( y - 1 ) + 3 ( y + 2 ) = 5 ( y - 4 )$$

Solve for y

$$y=-11$$

Steps for Solving Linear Equation

Use the distributive property to multiply 4 by y-1.

$$4y-4+3\left(y+2\right)=5\left(y-4\right)$$

Use the distributive property to multiply 3 by y+2.

$$4y-4+3y+6=5\left(y-4\right)$$

Combine 4y and 3y to get 7y.

$$7y-4+6=5\left(y-4\right)$$

Add -4 and 6 to get 2.

$$7y+2=5\left(y-4\right)$$

Use the distributive property to multiply 5 by y-4.

$$7y+2=5y-20$$

Subtract 5y from both sides.

$$7y+2-5y=-20$$

Combine 7y and -5y to get 2y.

$$2y+2=-20$$

Subtract 2 from both sides.

$$2y=-20-2$$

Subtract 2 from -20 to get -22.

$$2y=-22$$

Divide both sides by 2.

$$y=\frac{-22}{2}$$

Divide -22 by 2 to get -11.

$$y=-11$$