Solve 4(x-8)^2+10=10

$$4 ( x - 8 ) ^ { 2 } + 10 = 10$$

Solve for x

$$x=8$$

Steps by Finding Square Root

Subtract 10 from both sides of the equation.

$$4\left(x-8\right)^{2}+10-10=10-10$$

Subtracting 10 from itself leaves 0.

$$4\left(x-8\right)^{2}=10-10$$

Subtract 10 from 10.

$$4\left(x-8\right)^{2}=0$$

Divide both sides by 4.

$$\frac{4\left(x-8\right)^{2}}{4}=\frac{0}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$\left(x-8\right)^{2}=\frac{0}{4}$$

Divide 0 by 4.

$$\left(x-8\right)^{2}=0$$

Take the square root of both sides of the equation.

$$x-8=0 x-8=0$$

Add 8 to both sides of the equation.

$$x-8-\left(-8\right)=-\left(-8\right) x-8-\left(-8\right)=-\left(-8\right)$$

Subtracting -8 from itself leaves 0.

$$x=-\left(-8\right) x=-\left(-8\right)$$

Subtract -8 from 0.

$$x=8$$