Solve 4(x-3)leq-2(x+1)

$$4 ( x - 3 ) \leq - 2 ( x + 1 )$$

Solve for x

$$x\leq \frac{5}{3}$$

Solution Steps

Use the distributive property to multiply 4 by x-3.

$$4x-12\leq -2\left(x+1\right)$$

Use the distributive property to multiply -2 by x+1.

$$4x-12\leq -2x-2$$

Add 2x to both sides.

$$4x-12+2x\leq -2$$

Combine 4x and 2x to get 6x.

$$6x-12\leq -2$$

Add 12 to both sides.

$$6x\leq -2+12$$

Add -2 and 12 to get 10.

$$6x\leq 10$$

Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.

$$x\leq \frac{10}{6}$$

Reduce the fraction \frac{10}{6} to lowest terms by extracting and canceling out 2.

$$x\leq \frac{5}{3}$$