Solve 4(x+1)-3(x-1)=2x+3quad3.4x

$$4 ( x + 1 ) - 3 ( x - 1 ) = 2 x + 3 \quad 3.4 x$$

Solve for x

$$x=0.625$$

Steps for Solving Linear Equation

Use the distributive property to multiply 4 by x+1.

$$4x+4-3\left(x-1\right)=2x+3\times 3.4x$$

Use the distributive property to multiply -3 by x-1.

$$4x+4-3x+3=2x+3\times 3.4x$$

Combine 4x and -3x to get x.

$$x+4+3=2x+3\times 3.4x$$

Add 4 and 3 to get 7.

$$x+7=2x+3\times 3.4x$$

Multiply 3 and 3.4 to get 10.2.

$$x+7=2x+10.2x$$

Combine 2x and 10.2x to get 12.2x.

$$x+7=12.2x$$

Subtract 12.2x from both sides.

$$x+7-12.2x=0$$

Combine x and -12.2x to get -11.2x.

$$-11.2x+7=0$$

Subtract 7 from both sides. Anything subtracted from zero gives its negation.

$$-11.2x=-7$$

Divide both sides by -11.2.

$$x=\frac{-7}{-11.2}$$

Expand \frac{-7}{-11.2} by multiplying both numerator and the denominator by 10.

$$x=\frac{-70}{-112}$$

Reduce the fraction \frac{-70}{-112} to lowest terms by extracting and canceling out -14.

$$x=\frac{5}{8}$$