Solve 4(a-2b)^2+3a-6b

$$4 ( a - 2 b ) ^ { 2 } + 3 a - 6 b$$

Evaluate

$$\left(a-2b\right)\left(4a-8b+3\right)$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(a-2b\right)^{2}.

$$4\left(a^{2}-4ab+4b^{2}\right)+3a-6b$$

Use the distributive property to multiply 4 by a^{2}-4ab+4b^{2}.

$$4a^{2}-16ab+16b^{2}+3a-6b$$

Expand

$$4a^{2}-16ab+3a+16b^{2}-6b$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(a-2b\right)^{2}.

$$4\left(a^{2}-4ab+4b^{2}\right)+3a-6b$$

Use the distributive property to multiply 4 by a^{2}-4ab+4b^{2}.

$$4a^{2}-16ab+16b^{2}+3a-6b$$