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\frac{4\left(8x-1\right)^{2}}{4}=\frac{49}{4}
Divide both sides by 4.
\left(8x-1\right)^{2}=\frac{49}{4}
Dividing by 4 undoes the multiplication by 4.
8x-1=\frac{7}{2} 8x-1=-\frac{7}{2}
Take the square root of both sides of the equation.
8x-1-\left(-1\right)=\frac{7}{2}-\left(-1\right) 8x-1-\left(-1\right)=-\frac{7}{2}-\left(-1\right)
Add 1 to both sides of the equation.
8x=\frac{7}{2}-\left(-1\right) 8x=-\frac{7}{2}-\left(-1\right)
Subtracting -1 from itself leaves 0.
8x=\frac{9}{2}
Subtract -1 from \frac{7}{2}.
8x=-\frac{5}{2}
Subtract -1 from -\frac{7}{2}.
\frac{8x}{8}=\frac{\frac{9}{2}}{8} \frac{8x}{8}=-\frac{\frac{5}{2}}{8}
Divide both sides by 8.
x=\frac{\frac{9}{2}}{8} x=-\frac{\frac{5}{2}}{8}
Dividing by 8 undoes the multiplication by 8.
x=\frac{9}{16}
Divide \frac{9}{2} by 8.
x=-\frac{5}{16}
Divide -\frac{5}{2} by 8.
x=\frac{9}{16} x=-\frac{5}{16}
The equation is now solved.