Solve for z
z<0
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7z+1<\frac{4}{4}
Divide both sides by 4. Since 4 is positive, the inequality direction remains the same.
7z+1<1
Divide 4 by 4 to get 1.
7z<1-1
Subtract 1 from both sides.
7z<0
Subtract 1 from 1 to get 0.
z<0
Product of two numbers is <0 if one is >0 and the other is <0. Since 7>0, z must be <0.
Examples
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Matrix
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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